SPONSORED LINKS
I agree that your latest math looks convincing... > 810 * 10**6 = 772 * 2**20 > which means that IBM is being honest, but the program reporting on the 772 (cmos?) is counting in units of 2**20! ...but I'm still curious about the formatting issue... I have just checked a huge UNIX file server which we have here, which has disks of every size from 200 Meg to 2 Gigabytes. All of them show ~ 10% less space available for use than their nominal size. DOS may not use quite as much as Unix but still... ! According to Michael Verne's email, if chkdsk shows you 540 MB, and fdisk shows you 527 MB, the difference (13 MB) must be what's used for formatting. Meanwhile, cmos is counting in units of 2**20, because, as in your calculation for the 810 MB drive, 540 * 10**6 = 514 * 2**20 I promise this is my last post on this, but I'd like to know if you agree! Gen ----------------------------------------------------- Genevieve Cerf, Ph.D. E.E. Speech Recognition & Language Understanding Services NYNEX Science & Technology 500 Westchester Avenue White Plains, NY 10604 (914) 644-2407 FAX: (914) 644-2211 gen@nynexst.com