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First of all, bear in mind that the memory socket is designed for 3.3V circuits Secondly, for a 5V IC to work, it REQUIRES 5V!!!!! Third, according to Ohm's law, V=IR, where V=voltage, I=current, R=resistance. So for the 5V memory board to work, the thinkpad MUST output a 5V to the 5V module, or else, there will not be enough voltage for the module to distinguish 0 and 1. (I think anything > ~4.2 is considered 1. Don't quote me on this. I am not too sure). So the current output is now 5/R instead of 3.3/R. So the IBM tech is probably right......